“变量转换”的版本间差异

2016年6月9日 (四) 10:37的最新版本

IDL>print,round(5.1),round(5.9)
IDL> 5, 6

IDL>print,ceil(5.1),ceil(5.9)
IDL> 6, 6

IDL>print,floor(5.1),floor(5.9)
IDL> 5, 5

(1) if no absolute value exceeds 32767, then the array is returned as a type INTEGER instead of LONG

(2) NINT will work on strings, e.g. print,nint(['3.4','-0.9']) will give [3,-1], whereas ROUND() gives an error message

@@ 第4行： / 第4行： @@
  IDL> 5, 6
 *ceil:向上进
- IDL>print,round(5.1),round(5.9)
+ IDL>print,ceil(5.1),ceil(5.9)
  IDL> 6, 6
 *floor:截取整数
- IDL>print,round(5.1),round(5.9)
+ IDL>print,floor(5.1),floor(5.9)
  IDL> 5, 5
-*整数范围很小（long），要转换大的整数，加上/L64
+*结果是long型的整数，要转换更大的数，加上/L64
 *[[astro_lib]]中的nint程序，可以代替round，而且
-：*(1) if no absolute value exceeds 32767, then the array is returned as
+:(1) if no absolute value exceeds 32767, then the array is returned as a type INTEGER instead of LONG
+:(2) NINT will work on strings, e.g. print,nint(['3.4','-0.9']) will give [3,-1], whereas ROUND() gives an error message
-		as a type INTEGER instead of LONG
-：*(2) NINT will work on strings, e.g. print,nint(['3.4','-0.9']) will
+==消除变量==
-		give [3,-1], whereas ROUND() gives an error message
+*temporary(var)